Quick Q: Does [=] imply that all local variables will be copied? -- StackOverflow
Quick A: No, only the ones you actually use.
From StackOverflow:
Does [=] imply that all local variables will be copied?
When I write a lambda with
[=], does it mean that all my local variables will be copied into members of the created struct or can I assume that only those will that are actually used in the lambda?



As noted yesterday, the C++ Now 2013 conference has sold out well in advance. There's one other conference that sold out almost immediately we should also mention:
As interest in C++ continues to increase, not only are we seeing more C++ events, but they're selling out quickly.