Quick answer: Yes, use std::function.

This recent short question shows a concise and correct answer, along with a link to a previous more complex example.

Can lambda functions be recursive?

Here is a plain old recursive function:

int fak(int n)
{
    return (n <= 1) ? 1 : n * fak(n - 1);
}

How would I write such a recursive function as a lambda function?

[](int n) { return (n <= 1) ? 1 : n * operator()(n - 1); }
// error: operator() not defined
 
[](int n) { return (n <= 1) ? 1 : n * (*this)(n - 1); }
// error: this wasn't captured for this lambda function

Is there any expression that denotes the current lambda so it can call itself recursively?