basics

Auto: A Necessary Evil? -- Roger Orr

Roger Orr has written about the history and use of auto in ACCU's Overload 115:

Auto -- A Necessary Evil?

by Roger Orr

From the article:

The keyword auto now lets you declare variables where the compiler provides the actual type and the programmer is either unwilling or unable to name the actual type. The keyword can also be used in function definitions to let you provide the return type after the rest of the function declaration, which is useful when the return type depends on the type of the arguments.

As with any new keyword there are questions about usage –- at two levels. First of all, where and how are programmers permitted to use the new feature. Secondly, what guidance is there to sensible adoption of the new feature. I intend to start with by answering the first question and then subsequently focus on the second.

Explicit Is Better Than Implicit -- K-ballo

tales-of-cpp.PNGTales of C++, Episode 5:

Explicit Is Better Than Implicit

The Zen of Python tell us that Explicit is better than Implicit. This is good advice for any and all languages, but what are the implications in the C++ lands? There is one particular C++ feature that relates directly to that advice; one important enough that grants on its own the introduction of a keyword. That feature is user-defined conversions and that keyword is explicit.

GotW #93 Solution: Auto Variables, Part 2 -- Herb Sutter

The solution to the latest GotW problem is now available:

GotW #93 Solution: Auto Variables, Part 2

by Herb Sutter

From the article:

As you worked through these cases, perhaps you noticed a pattern: The cases are mostly very different, but what they have in common is that they illustrate reason after reason motivating why (and how) to use auto to declare variables.

Let’s dig in and see...

Quick Q: What type to return from a property-style "getter"? -- StackOverflow

Quick A: Reference to const.

c++11 -- Ownership and getters

I'm new to C++ and I have troubles wrapping my head around ownership, specifically with a getter. Here's some example code:

class GameObject {
public:
  Transform *transform();
private:
  Transform _transform;
};

I guess a raw pointer is unsafe to use as someone could access it later when the object doesn't exist anymore?

  1. So I thought about using a unique_ptr for the transform member, since GameObject is the only one that owns the transform. But I can't return that from the getter, can I? But then again, why would I ever use a unique_ptr in the first place instead of adding it as a member like above?
  2. So why not use a shared_ptr? It just seems wrong to me, I don't want to share ownership, GameObject is the owner and others may access it...
  3. So what is it? A reference? I guess shared_ptr seems the wisest choice, since others could safely keep a reference to transform, but what good is that if the enclosing GameObject got destroyed, rendering the transform useless? I'm probably just thinking about ownership the wrong wrong way here but every way seems wrong to me. Thanks for your help.

Quick Q: In a function template, why pass const T& vs. T&&? -- StackOverflow

Quick A: Because you want to not change the argument, or you want to forward it, respectively.

c++ rvalue reference and const qualifier

Among the many benefits of const qualification is to make an API more understandable, example:

template<typename T> int function1(T const& in);
// clearly, the input won’t change through function1

With the introduction of rvalue references, one can benefit from perfect forwarding but often const qualifiers are removed, example:

template<typename T> int function2(T&& in);
// can explicitly forward the input if it's an rvalue

Apart from documentation, is there a good way to describe that function2 won’t change its input?

GotW #92 Solution: Auto Variables, Part 1 -- Herb Sutter

The solution to the latest GotW problem is now available:

GotW #92 Solution: Auto Variables, Part 1 (updated for C++11/14)

by Herb Sutter

From the article:

When you’re new to auto, the key thing to remember is that you really are declaring your own new local variable. That is, “what’s on the left” is my new variable, and “what’s on the right” is just its initial value:

auto my_new_variable = its_initial_value;

You want your new variable to be just like some existing variable or expression over there, and be initialized from it, but that only means that you want the same basic type, not necessarily that other variable’s own personal secondary attributes such as top-level const-ness and reference-ness which are per-variable. For example, just because he’s const doesn’t mean you’re const, and vice versa.

It’s kind of like being identical twins: Andy may be genetically just like his brother Bobby and is part of the same family, but he’s not the same person; he’s a distinct person and can make his own choice of clothes and/or jewelry, go to be seen on the scene in different parts of town, and so forth. So your new variable will be just like that other one and be part of the same type family, but it’s not the same variable; it’s a distinct variable with its own choice of whether it wants to be dressed with const and/or a reference, may be visible to different threads, and so forth.

Remembering this will let us easily answer the rest of our questions...

GotW #90 Solution: Factories -- Herb Sutter

The solution to the latest GotW problem is now available:

GotW #90 Solution: Factories (updated for C++11/14)

by Herb Sutter

From the article:

Guideline: A factory that produces a reference type should return a unique_ptr by default, or a shared_ptr if ownership is to be shared with the factory.

Guideline: A factory that produces a non-reference type should return a value by default, and throw an exception if it fails to create the object. If not creating the object can be a normal result, return an optional<> value.